类别 全部 - work - force - potential

作者:sq tong 11 年以前

808

Electrostatic field

The text delves into various principles and equations related to electric fields and their interactions with matter. It begins by discussing the concept of polarization and how the net dipole moment is the sum of individual dipole moments.

Electrostatic field

Electric field

Polarization

Net dipole moment P=sum(p_i)
bounded charge area density

dot(P, n)

bounded charge density

-div(P)

Potential

V=k*int(dot(r, P(r'))/r^2)

Single dipole
Potential Energy

U=-dot(p, E)

Potential energy for two dipoles U=k/r^3 [3*dot(p1, r)dot(p2, r)-dot(p1,p2)]

Force dipole under the nonuniform field E will be exerted force

F=dot(p,grad(E))

Torque

N=cross(p,E)

special method

Multipole Expansion V(r)=k*int(charge density/|r-r'|) 1/|r-r'|=sum(r^-(n+1)*r'^n*Pn(cos(theta)))
quardole moment

V(r)=k*sum(r_i, r_j, Q_ij)/2r^3 Q_ij=int((3*r_i*r_j-r_i*r_j*delta_ij)*charge density)

dipole moment

V(r)= k*dot(p,r)/r^2 p = int(r'*charge(r'))

E=k/r^3 [3*dot(p, r)r-p]

monopole

V(r)=k/r int(charge density)

multipole

P0(x)=1 P1(x)=x P2(x)=1/2*(3x^2-1)

Separation of Variables
The Method of Images
Assume that everything is the same in the two problems. Energy, however, is not the same.
Laplace equation
Conductors and Second Uniqueness Theorem In a volume V surrounded by conductors and containing a specified charge density p, the electric field is uniquely determined if the total charge on each conductor is given. (The region as a whole can be bounded by another conductor, or else unbounded.)
Boundary Conditions and Uniqueness theoerms The solution to Laplace's equation in some volume V is uniquely determined if V is specified on the boundary surface S.
General soluton:

Electrostatic field

Work and Energy
Electrostatic pressure Conductor has charge, under electric field, it will exerted on force F=1/2 * charge area density * (Eabove + E below)
Potential energy W = 1/2 * volume integrate(charge density * V) W = 1/2 * volume integrate(epsilon * square(E))

Energy cannot be superposition

Work W=-line integrate(q * E) from state to end W=difference(q * V)
Boundary condition
difference(direaction derivative(V))=-charge area density/epsilon
difference(normal(E)) = charge area density/epsilon difference(parallel(E)) = 0
Field parameter
Field strength E =k* volume integrate (charge density / square(distance))

div(E)=charge density/epsilon, curl(E)=0

Potential V = k*volume integrate(charge density/distance)

E=-grad(V)

V=-line integrate (E) from reference to point

Charge density

div(grad(V))= - charge density/epsilon

V = volume integrate(charge density/distance)